题解 | 计算日期到天数转换 写个类就行吧

#include <climits>//小写一个类
#include <iostream>
#include<algorithm>
#include<cstring>
using namespace std;
class D {//手写类，挺好
  public:
    int year;
    int month;
    int day;
    bool run;
    D(int a, int b, int c): year(a), month(b), day(c), run(0) {
        if ((a % 4 == 0) && a % 100 != 0 || a % 400 == 0)run = 1;//计算具体天数
        else run = 0;

    }
    static int a[13];
    int f() {int sum=0;
        if (run == 0) {
            for (int i = 1; i < month; i++)sum += a[i];
            sum += day;
        } else {
            if (month <= 2) {
                for (int i = 1; i < month; i++)sum += a[i];
                sum += day;
            } else {
                {
                    for (int i = 1; i < month; i++)sum += a[i];
                    sum += day;
                    sum += 1;
                }
            }
        }
        return sum;
    }
};
int D::a[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int main() {
  
    int a1, b1, c;
    cin >> a1 >> b1 >> c;
    D seek(a1, b1, c);
    cout << seek.f() << endl;


}
// 64 位输出请用 printf("%lld")