采用优先队列解决问题

#include <iostream>
#include <queue>
#include <vector>
using namespace std;

int main()
{
    int N;
    while (cin >> N) {
        if (N == 0) break;
        priority_queue<int, vector<int>, greater<int>> pq;
        while (N--) {
            int val;
            cin >> val;
            pq.push(val);
        }
        int result = 0;
        while (pq.size() > 1) {
            int a = pq.top();
            pq.pop();
            int b = pq.top();
            pq.pop();
            pq.push(a+b);
            result += a + b;
        }
        cout << result << endl;
    }
    return 0;
}