题解 | #KiKi去重整数并排序#

import java.util.Scanner;
import java.util.Arrays;
public class Main {
    
    public static void main(String[] args) {
        
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int[] array = new int[n];
        int[] arrayPai = new int[n];
        int count = 0;    // 记录重复的个数
        int index = 0;
        boolean isChong = false;
        for(int i = 0 ; i < n ; i++) {
            array[i] = sc.nextInt();
        }
        for(int i = 0 ; i < n ; i++) {
            for(int j = 0 ; j < i ; j++) {
                if(array[i] == array[j]){
                    isChong = true;
                    count++;
                    break;
                } else {
                    isChong = false;
                }
            }
            if(!isChong) {
                arrayPai[index++] = array[i];
            }
        }
        int[] re = new int[n - count];
        for(int i = 0 ; i < n - count ; i++) {
            re[i] = arrayPai[i];
        }
        Arrays.sort(re);
        for(int i = 0 ; i < n - count ; i++) {
            System.out.print(re[i] + " ");
        }
        
    }
}