题解 | 凯撒解密

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 进行凯撒解密
# @param password string字符串 旺仔哥哥的密码
# @param n int整型 每个字符加密过程中错位的次数
# @return string字符串
#
class Solution:
    def decodeWangzai(self , password: str, n: int) -> str:
        res = 'abcdefghijklmnopqrstuvwxyz'
        result = ''
        for i in password:
            address = res.index(i) - n%26
            result += res[address]
        return result