福哥答案2020-09-26:

变量定义:c++是别名。rust是指针。
取地址和按位与,c++和rust是相同的。

c++测试代码如下:

#include <iostream>
struct Point {
    int x;
    int y;
};

int main()
{
    Point p1 = { 25,25 };
    printf("p1.x address:%d\r\n", &p1.x);
    printf("p1 address:%d\r\n", &p1);
    Point& p2 = p1;
    printf("p2.x address:%d\r\n", &p2.x);
    printf("p2 address:%d\r\n", &p2);
    printf("p1和p2地址相同,说明p2起到了别名的作用。p2.x和p2地址相同,说明p2保存的是内容,而不是地址。\r\n");
    std::system("pause");
    return 0;
}

运行结果如下:
图片说明
rust测试代码如下:

struct Point {
    x: i64,
    y: i64,
}

fn main() {
    let p1 = Point { x: 25, y: 25 };
    println!("p1.x address: {:p}", &p1.x);
    println!("p1 address: {:p}", &p1);
    let p2: &Point = &p1;
    println!("p2.x address: {:p}", &p2.x);
    println!("p2 address: {:p}", &p2);
    println!("p1和p2地址不同,说明p2不是p1的别名。p2.x和p2地址不同,说明p2是指针。");
}

运行结果如下:
图片说明


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