//解题思路:递归,将小的左右头节点 public ListNode Merge(ListNode list1,ListNode list2) { if(list1 == null) { return list2; } if(list2 == null) { return list1; } ListNode head = null; if(list1.val < list2.val) { head = list1; head.next = Merge(list1.next, list2); } else { head = list2; head.next = Merge(list1, list2.next); } return head; }