1、判断是否是兄弟单词 2、找到所有的兄弟单词,并排序 3、如果k小于等于单词的总数,则输出字典顺序的第k个,数组索引k-1;否则不需要输出

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNextLine()) { // 注意 while 处理多个 case
            String[] map = in.nextLine().split("\\s+");
            int len = map.length;
            int num = Integer.parseInt(map[0]);//待查找的个数
            int k = Integer.parseInt(map[len-1]);
            String x = map[len-2];
            int count = 0;
            ArrayList<String> list = new ArrayList<>();
            for(int i=1;i<=num;i++){
                if(isBrotherWord(map[i],x)){
                    count++;
                    list.add(map[i]);
                }
            }
            String[] res = new String[list.size()];
            int index = 0;
            for(String s:list){
                res[index++] = s;
            }
            Arrays.sort(res);
            System.out.println(count);
            if(k<=count){//要查找的k小于等于总数count
                System.out.println(res[k-1]);//第K个的索引是k-1
            }
        }
    }
    public static boolean isBrotherWord(String s1,String s2){
        if(s1.length() != s2.length()){
            return false;
        }else if(s1.equals(s2)){
            return false;
        }else{
            char[] cha1 = s1.toCharArray();
            Arrays.sort(cha1);
            char[] cha2 = s2.toCharArray();
            Arrays.sort(cha2);
            if(!new String(cha1).equals(new String(cha2))){
                return false;
            }else{
                return true;
            }
        }
    }
}