题解 | #蛇形矩阵#

n = eval(input())
num = 1
ls = [([0] * n) for i in range(n)] #构造一个nxn的0矩阵

for a in range(n): 
    row = a
    col = 0

    for i in range(a+1):
        ls[row][col] = num
        row -= 1
        col += 1
        num += 1

for i in range(n):  #将列表按要求的字符串输出
    for j in range(n):
        if ls[i][j] !=0:
            print(ls[i][j],end=' ')
    print('\r')