设10进制数字为20

10转2：bin(20) 0b10100

10转8：oct(20) 0o24

10转16：hex(20) 0x14

2转10：int("0b10100",2)

8转10：int("0o24",8)

16转10：int("0x14",16)

l2 = []
l8 = []
l16 = []
n = 20
for i in range(n):
    l2.append(bin(i))
    l8.append(oct(i))
    l16.append(hex(i))

print(l2)
print(l8)
print(l16)

for i in range(n):
    print(int(l2[i],2), end="   ")
    print(int(l8[i], 8), end="   ")
    print(int(l16[i], 16))