题解 | #对称平方数1#

#include<cstdio>
using namespace std;
int Reverse(int n){
	int reverse = 0;
	int remain;
	while(true){
		remain = n%10;
		reverse = 10*reverse + remain;
		n = n/10;
		if(n == 0){
			break;
			}
		}
	return reverse;
	}

int main(){
	int i = 0;
	for(i = 0; i <= 256; ++i){
		if(i*i == Reverse(i*i)){
			printf("%d\n",i);
			}
		}
	}