题解 | #井字棋#

#include <stdio.h>

int main() {

    char arr[3][3] = { 0 };
    for (int i = 0; i < 3; i++)
    {
       for (int j = 0; j < 3; j++)
       {
           scanf("%c", arr[i] + j);
           getchar();
       }
    }

    for (int i = 0; i < 3; i++)
    {
        if (arr[i][0] == arr[i][1] && arr[i][1] == arr[i][2])
        {
            if (arr[i][0] == 'K')
            {
                printf("KiKi wins!");
                return 0;
            }
            else if (arr[i][0] == 'B')
            {
                printf("BoBo wins!");
                return 0;
            }
        }

        if (arr[0][i] == arr[1][i] && arr[1][i] == arr[2][i])
        {
            if (arr[0][i] == 'K')
            {
                printf("KiKi wins!");
                return 0;
            }
            else if (arr[0][i] == 'B')
            {
                printf("BoBo wins!");
                return 0;
            }
        }
    }

    if (arr[0][0] == arr[1][1] && arr[1][1] == arr[2][2])
    {
        if (arr[0][0] == 'K')
        {
            printf("KiKi wins!");
            return 0;
        }
        else if (arr[0][0] == 'B')
        {
            printf("BoBo wins!");
            return 0;
        }
    }

    if (arr[0][2] == arr[1][1] && arr[1][1] == arr[2][0])
    {
        if (arr[0][2] == 'K')
        {
            printf("KiKi wins!");
            return 0;
        }
        else if (arr[0][2] == 'B')
        {
            printf("BoBo wins!");
            return 0;
        }
    }

    printf("No winner!");

    return 0;
}