select user_id,g.room_id,room_type, date(checkout_time)-date(checkin_time) as days from guestroom_tb as g join ( select room_id,user_id,checkin_time,checkout_time from checkin_tb ) as c on g.room_id = c.room_id where date(checkout_time)-date(checkin_time) >= 2 order by days asc,g.room_id asc,user_id desc

京公网安备 11010502036488号