select
difficult_level,
round(sum(
if(qp.result='right',1,0)
)/count(qp.question_id),4)
as
correct_rate
from
question_detail as qt
join
question_practice_detail as qp
on
qt.question_id = qp.question_id
join
user_profile as ue
on
ue.device_id = qp.device_id
where
ue.university = '浙江大学'
group by
qt.difficult_level
order by
correct_rate
;

京公网安备 11010502036488号