select
case when au.author_level in (5,6) then '5-6级'
when au.author_level in (3,4) then '3-4级'
when au.author_level in (1,2) then '1-2级'
end as level_cnt, count(issue_id) as num
from
author_tb au join answer_tb an
on
au.author_id = an.author_id
where
an.char_len > 100
group by
level_cnt
order by
num desc

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