题解 | #名字的漂亮度#

#题解1
# # import sys
# #计算名字分数
# #创建一个字典,统计字符的个数,然后按照个数排序.个数越多,用越多的漂亮度
# def get_score(name):
#     dic = {}
#     for c in name:
#         if c in dic:
#             dic[c] += 1
#         else:
#             dic[c] = 1
#     t_list = list(dic.values())
#     t_list.sort(reverse = True)
#     #只需要知道重复字符的个数,排序.重复个数越多的,用越多的漂亮度
#     score = 0
#     for i in range(len(t_list)):
#         score += (26 - i) * t_list[i]
#     return score

# while True:
#     try:
#         num = int(input())
#         for i in range(num):
#             print(get_score(input()))
#     except:
# #         print(sys.exc_info())
#         break



#题解2 
# import sys
#计算名字分数
#使用集合收集名字里不重复的字符,再使用字符串函数count统计字符个数,个数越多的,用越多的漂亮度
def get_score(name):
    s = set(name)
    t_list = []
    for c in s:
        t_list.append(name.count(c))
    t_list.sort(reverse = True)
    score = 0
    for i in range(len(t_list)):
        score += (26 - i) * t_list[i]
    return score

while True:
    try:
        num = int(input())
        for i in range(num):
            print(get_score(input()))
    except:
#         print(sys.exc_info())
        break