这个题貌似就是让你找逆序对?emm...没啥好说的.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=2e5+5;
ll sum[N];//建树
ll a[N],n;
ll Greater[N];//左边比它大的数.
ll Less[N];//左边比它小的数.
int lowbit(int x)
{
return x&(-x);
}
void insert(int pos,int val)
{
while(pos<=n)
{
sum[pos]+=val;
pos+=lowbit(pos);
}
}
int query(int pos)
{
ll res=0;
while(pos>0)
{
res+=sum[pos];
pos-=lowbit(pos);
}
return res;
}
int main()
{
ll ans1=0,ans2=0;
int x;
cin>>n;
for(int i=1;i<=n;i++)
{
scanf("%lld",&a[i]);
Greater[i]=query(n)-query(a[i]);
Less[i]=query(a[i]-1);
insert(a[i],1);
}
memset(sum,0,sizeof sum);
for(int i=n;i>=1;i--)
{
ans1+=Greater[i]*(query(n)-query(a[i]));
ans2+=Less[i]*(query(a[i]));
insert(a[i],1);
}
cout<<ans1<<' '<<ans2<<endl;
return 0;
}

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