with t_follower_id as (
select follower_id
from follow
where user_id=1
)
select music_name
from follow a
join music_likes b on a.follower_id=b.user_id
join music c on b.music_id=c.id
where follower_id in (select * from t_follower_id)
and music_id not in (select music_id from music_likes where user_id=1)
group by music_name
order by max(music_id)
GROUP BY 和 ORDER BY 的列不一致,会报错:
select music_name from tb_xxx group by music_name order by music_id
在GROUP BY聚合查询中,ORDER BY子句只能引用GROUP BY子句中的列或聚合函数:
select music_name from tb_xxx group by music_name, music_id order by music_id -- 或者: select music_name from tb_xxx group by music_name order by max(music_id)

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