题解 | #课程冲突#

#include <iostream>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;

int main() {
    int n;
    cin >> n;
    
    vector<string> subject[50];  // 存储每个时间段的课程
    vector<int> conflicts;       // 存储发生冲突的时间
    
    // 读取课程信息
    for (int i = 0; i < n; i++) {
        int time;
        string code;
        cin >> time >> code;
        
        // 如果该时间已有课程，记录冲突
        if (subject[time].size() == 1) {
            conflicts.push_back(time);
        }
        subject[time].push_back(code);
    }
    
    // 输出结果
    if (conflicts.empty()) {
        cout << "YES" << endl;
    } else {
        // 按时间排序
        sort(conflicts.begin(), conflicts.end());
        
        // 输出冲突信息
        for (int time : conflicts) {
            printf("%02d", time);  // 输出时间，保证两位数
            for (const string& code : subject[time]) {
                cout << " " << code;
            }
            cout << endl;
        }
    }
    
    return 0;
}

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        
        ArrayList<String>[] subject = new ArrayList[50];
        ArrayList<Integer> conflicts = new ArrayList<>();
        
        // 初始化数组
        for (int i = 0; i < 50; i++) {
            subject[i] = new ArrayList<>();
        }
        
        // 读取课程信息
        for (int i = 0; i < n; i++) {
            int time = sc.nextInt();
            String code = sc.next();
            
            if (subject[time].size() == 1) {
                conflicts.add(time);
            }
            subject[time].add(code);
        }
        
        // 输出结果
        if (conflicts.isEmpty()) {
            System.out.println("YES");
        } else {
            Collections.sort(conflicts);
            
            for (int time : conflicts) {
                System.out.printf("%02d", time);
                for (String code : subject[time]) {
                    System.out.print(" " + code);
                }
                System.out.println();
            }
        }
    }
}

n = int(input())
subject = [[] for _ in range(50)]  # 存储每个时间段的课程
conflicts = []  # 存储发生冲突的时间

# 读取课程信息
for _ in range(n):
    time, code = input().split()
    time = int(time)
    
    # 如果该时间已有课程，记录冲突
    if len(subject[time]) == 1:
        conflicts.append(time)
    subject[time].append(code)

# 输出结果
if not conflicts:
    print("YES")
else:
    # 按时间排序
    conflicts.sort()
    
    # 输出冲突信息
    for time in conflicts:
        print(f"{time:02d}", end="")  # 输出时间，保证两位数
        for code in subject[time]:
            print(f" {code}", end="")
        print()