python3题解 | #跳台阶#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param number int整型 
# @return int整型
#
class Solution:
    def jumpFloor(self , number: int) -> int:
        # write code here
        # if number <=2:
        #     return number
        # else:
        #     dp = [None for _ in range(number+1)]
        #     dp[1] = 1
        #     dp[2] = 2
        #     for i in range(3,number+1):
        #         dp[i] = dp[i-1] + dp[i-2]
        #     return dp[number]
        if number<=2:
            return number
        else:
            # dp = [None for _ in range(number+1)]
            dp = [0 for _ in range(number+1)]
            dp[1] = 1
            dp[2] = 2
            for i in range(3,number+1):
                dp[i] = dp[i-1] + dp[i-2]
            return dp[number]