class Solution: # 返回对应节点TreeNode def KthNode(self, pRoot, k): # write code here def dfs(root): if not root: return dfs(root.left) if self.count == 0: return self.count -= 1 if self.count == 0: self.ans = root dfs(root.right) if not pRoot or k <= 0: return None self.count = k self.ans = None dfs(pRoot) return self.ans