题解 | #扫雷#

int output(int x, int y, int z, int k, char ch[][k]) {
    int count = 0;
    //在当前值周围进行循环判断
    for (int i = x - 1; i <= x + 1; i++) {
        for (int j = y - 1; j <= y + 1; j++) {
            //若有*且不超出矩阵范围，地雷加1
            if (ch[i][j] == '*' && i >= 0 && i < z && j >= 0 && j < k) 
                count++;
        }
    }
    return count;  //返回地雷数
}
int main() {
    int n, m, count = 0;
    scanf("%d %d\n", &n, &m);
    char ch[n][m];
    //依次输入字符
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            scanf("%c ", &ch[i][j]);
        }
    }
    //依次判断并输出字符
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < m; j++) {
            if (ch[i][j] != '*') {  //字符不为*时，计算当前值应为多少
                ch[i][j] = output(i, j, n, m, ch);  //字符替换地雷数值
                printf("%d", ch[i][j]);  //输出当前值
            } else printf("%c", ch[i][j]);  //字符为*时，直接输出
        }
        printf("\n");
    }
    return 0;
}