题解 | #创建动态数组#

#include <iostream>
using namespace std;

int main() {

    int n;
    cin >> n;
    
    // write your code here......
    int *a = new int[n];
    for (int i=0;i <= 2*n-1;i++){
        a[i] = n+i;
    }
    for (int i=0;i < n;i++){
        cout << a[i] << " ";
    }
    return 0;
}