题解 | #直角三角形#

//实现判断此三角形是不是直角三角形，并输出此三角形的周长。
#include<stdio.h>
#include<math.h>
int main() {
    int m;
    scanf("%d", &m);
    int x1, y1, x2, y2, x3, y3;
    for (int i = 1; i <= m; i++) {
        scanf("%d%d%d%d%d%d", &x1, &y1, &x2, &y2, &x3, &y3);
        double r1 = sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2));
        double r2 = sqrt((x1 - x3) * (x1 - x3) + (y1 - y3) * (y1 - y3));
        double r3 = sqrt((x2 - x3) * (x2 - x3) + (y2 - y3) * (y2 - y3));
       double sum = r1 + r2 + r3;
        if ((r1 * r1 == r2 * r2 + r3 * r3 ) || ( r2 * r2 == r1 * r1 + r3 * r3 ) ||
                (r3 * r3 == r2 * r2 + r1 * r1))
            printf("Yes\n");
        else
            printf("No\n");
        printf("%.2lf\n", sum);

    }

    return 0;

}