select qd.difficult_level,
count(
CASE
WHEN qpd.result = 'right' THEN 1
END
)/count(qpd.question_id) as correct_rate
from
question_practice_detail qpd
join
question_detail qd
on qpd.question_id = qd.question_id
join
user_profile u
on u.device_id = qpd.device_id
where
u.university = "浙江大学"
group by
qd.difficult_level
order by
correct_rate



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