题解 | #牛牛的线段#

#include<stdio.h>
#include<math.h>
int main()
{
	int x1, y1 = 0; 
	int x2, y2 = 0;  
	scanf("%d%d%d%d", &x1, &y1, &x2, &y2);  
	int x = x1 - x2;  
	int y = y1 - y2; 
	int p = pow(x, 2) + pow(y, 2); 
	printf("%d", p);  
	return 0; 
}