题解 | 从单向链表中删除指定值的节点

import sys

for line in sys.stdin:
    a = line.split()

outputList = list()

outputList.append(int(a[1]))

for i in range(2,int(a[0])+1):
    numLoc = outputList.index(int(a[2*i - 1]))
    outputList.insert(numLoc+1,int(a[2*i-2]))

outputList.remove(int(a[-1]))

strRes = " ".join(map(str,[i for i in outputList]))

print(strRes)