实在是此类题目,多找找规律,傻乎乎递归写了好久
#include<iostream>
using namespace std;
int main()
{
int n;
while (cin >> n && n != 0)
{
int a =n/2;
cout << a << endl;
}
return 0;
}
实在是此类题目,多找找规律,傻乎乎递归写了好久
#include<iostream>
using namespace std;
int main()
{
int n;
while (cin >> n && n != 0)
{
int a =n/2;
cout << a << endl;
}
return 0;
}