题目链接:https://ac.nowcoder.com/acm/contest/3003/G
判断一个式子是不是成立。直接快速幂明显会爆,上取模快速幂,模数1e9+7;
这样就过了,也不知道为啥:

#include <iostream>
#include <cstring>
#include <queue>
#include <algorithm>
#include <cmath>
#include <map>
#include <set>

#define il inline
#define ll long long
#define LL long long
using namespace std;
const int maxn = 1e5 + 10;
const ll inf = 0x7ffffffffff;
const ll mod = 1e9+7;

template<class T>
inline void read(T &res) {
    char c;
    T flag = 1;
    while ((c = getchar()) < '0' || c > '9')if (c == '-')flag = -1;
    res = c - '0';
    while ((c = getchar()) >= '0' && c <= '9')res = res * 10 + c - '0';
    res *= flag;
}

ll t;
ll qpow(ll a,ll b){
    ll ans=1;;
    a%=mod;
    while(b){
        if(b&1) ans=(ans*a)%mod;
        a=(a*a)%mod;
        b>>=1;
    }
    return ans%mod;
}
int main() {
    ll n;
    cin>>t;
    while(t--){
        ll a,b,c,d,e,f,g;
        cin>>a>>b>>c>>d>>e>>f>>g;
        if(qpow(a,d)+qpow(b,e)+qpow(c,f)==g){
            cout<<"Yes"<<endl;
        }
        else cout<<"No"<<endl;
    }
    return 0;
}