Problem Description
Collecting one's own plants for use as herbal medicines is perhaps one of the most self-empowering things a person can do, as it implies that they have taken the time and effort to learn about the uses and virtues of the plant and how it might benefit them, how to identify it in its native habitat or how to cultivate it in a garden, and how to prepare it as medicine. It also implies that a person has chosen to take responsibility for their own health and well being, rather than entirely surrender that faculty to another. Consider several different herbs. Each of them has a certain time which needs to be gathered, to be prepared and to be processed. Meanwhile a detailed analysis presents scores as evaluations of each herbs. Our time is running out. The only goal is to maximize the sum of scores for herbs which we can get within a limited time.
 

Input
There are at most ten test cases.
For each case, the first line consists two integers, the total number of different herbs and the time limit.
The i-th line of the following n line consists two non-negative integers. The first one is the time we need to gather and prepare the i-th herb, and the second one is its score.

The total number of different herbs should be no more than 100. All of the other numbers read in are uniform random and should not be more than 109.
 

Output
For each test case, output an integer as the maximum sum of scores.
 

Sample Input
3 70 71 100 69 1 1 2
 

Sample Output
3
 

Source
2016 ACM/ICPC Asia Regional Qingdao Online
 

由于背包的容量太大导致不能用递推的01背包，也不是我想象中的贪心，而是搜索，不仅要排序，还要后缀优化，尼玛，都没听说过啊，要不是暑假做01背包的课件，boss当时说了有递推和递归，我都不知道可以写成搜索……

//358MS	1788K	1372B	C++  2016-09-20 11:12:56
#include <iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
struct node
{
    long long value,cost;
}num[120];
bool cmp(node x,node y)
{
    return x.cost>y.cost;
}
long long numvalue[120],numcost[120];
int n;
long long sum,tot;
void dfs(int x,long long costsum,long long valuesum)
{
    //printf("x=%d,costsum=%lld,valuesum=%lld\n",x,costsum,valuesum);
    if(x==n+1)
    {
        if(valuesum>tot)tot=valuesum;
        return;
    }
    if(valuesum+numvalue[x]<=tot)return;
    if(costsum+numcost[x]<=sum)
    {
        if(valuesum+numvalue[x]>tot)tot=valuesum+numvalue[x];
     //   printf("tot=%lld\n",tot);
        return;
    }
    if(costsum+num[x].cost<=sum)
        dfs(x+1,costsum+num[x].cost,valuesum+num[x].value);
    dfs(x+1,costsum,valuesum);
}
int main()
{
  //  freopen("cin.txt","r",stdin);
    while(~scanf("%d%lld",&n,&sum))
    {
        for(int i=1;i<=n;i++)scanf("%lld%lld",&num[i].cost,&num[i].value);
        sort(num+1,num+1+n,cmp);
        numvalue[n+1]=numcost[n+1]=0;
        for(int i=n;i>=1;i--)numvalue[i]=numvalue[i+1]+num[i].value,numcost[i]=numcost[i+1]+num[i].cost;
       // for(int i=1;i<=n;i++)printf("i=%d,value=%lld,cost=%lld\n",i,numvalue[i],numcost[i]);
        tot=0LL;
        dfs(1,0LL,0LL);
        cout<<tot<<endl;
    }
    return 0;
}