select
qd.difficult_level,
round(
sum(
case
when qpd.result = 'right' then 1
else 0
end
) / count(qpd.question_id),
4
) as correct_rate
from
user_profile up
inner join question_practice_detail qpd on up.device_id = qpd.device_id
inner join question_detail qd on qpd.question_id = qd.question_id
where
up.university = '浙江大学'
group by
qd.difficult_level
order by
correct_rate asc;

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