m存储前i项和对应下标,a存储前i项和,ans最大长,即求第i项时m[a-k]是否存在
def solve(l, n, k):
m = {0:-1}
a = ans = 0
for i in range(n):
a += l[i]
if a not in m.keys():
m[a] = i
if a - k in m.keys():
ans = max(ans, i - m[a-k])
return ans
while True:
try:
n, k = map(int, input().split())
l = list(map(int, input().split()))
print(solve(l, n, k))
except EOFError:
break
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