#include <stdio.h>

int main() {
    int h,r;
    float pai=3.14;
    scanf("%d %d",&h,&r);
    float V = pai*h*r*r;
    float n = 10000/V;
    printf("%d",(int)(n+1));//(类型)(param+0.5)代表四舍五入   此处不舍小数,应+1
    return 0;
}