#include <stdio.h> int main() { int h,r; float pai=3.14; scanf("%d %d",&h,&r); float V = pai*h*r*r; float n = 10000/V; printf("%d",(int)(n+1));//(类型)(param+0.5)代表四舍五入 此处不舍小数,应+1 return 0; }