题解 | #数值的整数次方#

class Solution {
public:
    double Power(double base, int exponent) {
        double ans=1;
        if(exponent>=0)
        {
            for(int i=0;i<exponent;i++)
            {
                ans*=base;
            }
            return ans;
        }
        exponent=-exponent;
        for(int i=0;i<exponent;i++)
        {
            ans/=base;
        }
        return ans;
    }
};