/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ #include <tuple> class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ tuple<ListNode*,ListNode*,ListNode*> ReverseListWithEndNode(ListNode* head, int d) { // write code here auto *prev = new ListNode(head->val); auto *last = prev; int i = 0; ListNode *node = head->next; while(node!=nullptr && i<d){ auto next = new ListNode(node->val); next->next = prev; prev = next; node = node->next; i++; } // 返回三个值 反转链表prev, 原表最后一个节点node,原表第一个节点last return make_tuple(prev, node, last); } ListNode* reverseBetween(ListNode* head, int m, int n) { // write code here int i=0; ListNode *root, *temp, *node=head; if(m>1){ root = new ListNode(head->val); node = head->next; temp = root; i++; } for(;node!=nullptr;node=node->next,i++){ if(i>=m-1 && i<=n-1){ auto out = ReverseListWithEndNode(node, n-m); auto *prev = get<0>(out); auto *next = get<1>(out); auto *last = get<2>(out); if(m==1){ root = prev; temp = last; node = next; } else{ temp->next = prev; temp = last; } last->next = next; node = last; i = n; if(node==nullptr) break; }else{ auto *next = new ListNode(node->val); temp->next = next; temp = next; } } return root; } };