Python题解 | #识别有效的IP地址和掩码并进行分类统计#

a = b = c = d = e = wrongIP = privateIP = 0
import re

def bins(strs):
    results = ""
    strs = strs.split(".")
    for i in strs:
        b = str(bin(int(i)))[2:]
        if len(b) < 8:
            results += (8-len(b))*"0"+b
        else:
            results += b
    return results

def wrongIPs(macs):
    if macs[0] == "0":
        return 1
    if macs.count("1") == 32:
        return 1
    num_1 = macs.count("1")
    if macs == num_1*"1" + (32-num_1)*"0":
        return 0
    else:
        return 1

def privateIPs(ips):
    ips = ips.split(".")
    ips_0 = ips[0]
    ips_1 = ips[1]
    ips_2 = ips[2]
    ips_3 = ips[3]
    if int(ips_1) <= 255 and int(ips_2) <= 255 and int(ips_3) <= 255:
        if ips_0 == "10":
            return 1
        if ips_0 == "172" and 16<=int(ips_1)<=31:
            return 1
        if ips_0 == "192" and ips_1 == "168":
            return 1
    else:
        return 0

try:
    while True:
        inpt = str(input())
        ips = inpt.split("~")
        if re.findall(r"^\d+.\d+.\d+.\d+$", ips[0]) and re.findall(r"^\d+.\d+.\d+.\d+$", ips[1]):
            if wrongIPs(bins(ips[1])):
                wrongIP += wrongIPs(bins(ips[1]))
            else:
                if privateIPs(ips[0]):
                    privateIP += privateIPs(ips[0])

                ips_0 = ips[0].split(".")
                if int(ips_0[1]) <= 255 and int(ips_0[2]) <= 255 and int(ips_0[3]) <= 255:
                    if 1 <= int(ips_0[0]) <= 126:
                        a += 1
                    if 128 <= int(ips_0[0]) <= 191:
                        b += 1
                    if 192 <= int(ips_0[0]) <= 223:
                        c += 1
                    if 224 <= int(ips_0[0]) <= 239:
                        d += 1
                    if 240 <= int(ips_0[0]) <= 255:
                        e += 1
                else:
                    wrongIP += 1
        else:
            wrongIP += 1
except:
        print(a, b, c, d, e, wrongIP, privateIP)