题解 | 牛牛的短信

#include <stdio.h>

float count(int n,int* number)
{
   int i = 0;
   float total=0;
   for(i = 0;i<n;i++)
   {
     if(number[i]<=60){
        total += 0.1;
     }
     else{
        total+=0.2;
     }
   }
   return total;
}

int main() {
    int n = 0;
    int i = 0;
    scanf("%d",&n);
    int number[n];
    if(n>0)
    {
        for(i = 0;i<n;i++)
        {
           scanf("%d",&number[i]);
        }
    }

float total = count(n,number); 
    printf("%.1f",total);
    return 0;
}