题解 | #跳台阶#

跳台阶问题

1. 记忆化搜索

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param number int整型 
# @return int整型
#
class Solution:
    def __init__(self):
        self.mem = {}
    
    def jumpFloor(self , number: int) -> int:
        # write code here
        if number == 0:
            return 0
        return self.subJumpFloor(number)
        
    
    def subJumpFloor(self, number: int) -> int:
        if number in self.mem:
            return self.mem[number]
        else:
            if number < 0:
                return 0
            if number == 0:
                return 1
            else:
                self.mem[number] = self.subJumpFloor(number - 1) + self.subJumpFloor(number - 2)
                return self.mem[number]