题解 | #获取字符串中各个字符的数量#

import java.util.*;

public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); String line = scanner.nextLine(); Map<Character, Integer> map = new LinkedHashMap<Character, Integer>();

    //write your code here......
    //先去除字符串中的非字母字符
    line = line.replaceAll("[^a-zA-Z]", "");
    //将字符的每个元素插入到map中
    //如果map中存在这个KEY就将value的值加1
    //如果不存在这个KEY就向map中添加键为该元素，值为1
    for(int i=0;i<line.length();i++){
        if(map.get(line.charAt(i))==null){
            map.put(line.charAt(i),1);
        }else{
            map.put(line.charAt(i),map.get(line.charAt(i))+1);
        }
    }
    Set<Map.Entry<Character, Integer>> entrys = map.entrySet();
    for (Map.Entry<Character, Integer> entry : entrys) {
        System.out.println(entry.getKey() + ":" + entry.getValue());
    }
}

}