特殊乘法简便解法

特殊乘法结果为x，y所有位和的乘积
如123 * 45 = 14 +15 +24 +25 +34+3*5
= 1(4+5)+2(4+5)+3(4+5)
= (1+2+3)*(4+5)

#include<iostream>
using namespace std;

int statusSum(int num){ //求十进制数所有位的和
    int sum=0;
    while(num>0){
        sum+=num%10;
        num=num/10;
    }
    return sum;
}
int main(){
    int x,y;
    cin>>x>>y;
    cout<<statusSum(x)*statusSum(y);
}