题解 | #在字符串中找出连续最长的数字串#

import java.util.Scanner;
import java.util.*;

// 纯属考察基本的字符串api调用熟练程度，没有算法可言
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextLine()) { // 注意 while 处理多个 case
            String s = in.nextLine();
            ArrayList<String> res = find(s);
            StringBuilder builder = new StringBuilder();
            if(res.size() == 1) {
              System.out.println(res.get(0) +"," + res.get(0).length());  
            } else {
                for(String item : res) {
                    builder.append(item);
                }
                System.out.println(builder.toString() + "," + res.get(0).length());
            }
        }
    }

    public static ArrayList<String> find(String s) {
        char[] cs = s.toCharArray();
        ArrayList<String> res = new ArrayList<String>();
        int maxlen = 0;
        for(int i = 0; i < cs.length;) {
            if(Character.isDigit(cs[i])) {
                int start = i;
                int off = 0;
                while(i < cs.length && Character.isDigit(cs[i])) {
                    off++;
                    i++;
                }
                if(off > maxlen) {
                    res.clear();
                    res.add(new String(cs, start, off));
                    maxlen = off;
                } else if(off == maxlen) {
                    res.add(new String(cs, start, off));
                }                 
            } else {
                i++;
            }
        }
        return res;
    }
}