题解 | #数组元素反转#

using namespace std;

int main() {

    int arr[6] = { 0 };

    int len = sizeof(arr) / sizeof(int);
    
    for (int i = 0; i < len; i++) {
        cin >> arr[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    int shu[6]={0};
    for(int i=len-1;i>=0;i--){
        shu[len-i-1]=arr[i];
    }
    // write your code here......
    

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << shu[i] << "]" << endl;
            break;
        }
        cout << shu[i] << ", ";
    }

    return 0;
}