题解 | 牛牛的替换

#include <stdio.h>
#include "string.h"

int main() {
	int n;

	char a1, a2, a3, a4;
	scanf("%d %c %c %c %c", &n, &a1, &a2, &a3, &a4);
	char str[n];
	getchar();
	scanf("%s", str);
	for (int i = 0; i < n; i++) {
		if (str[i] == a1)
			str[i] = a2;
	}
	for (int i = 0; i < n; i++) {
		if (str[i] == a3)
			str[i] = a4;
	}
	printf("%s", str);
	return 0;
}