#include <iostream>
using namespace std;

int main() {
    float hight;
    cin >> hight;
    float s = 0;
    for(int i = 0;i < 5;i++){
        s =s+ hight + hight/2;
        hight = hight/2;
    }
    cout << s - hight<< endl;
    cout << hight << endl;
}
// 64 位输出请用 printf("%lld")

不知道为啥是中等题。

用个float解决小数问题就完事了