题解 | 计算糖果

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    int A_B, B_C, AB, BC;
    cin >> A_B >> B_C >> AB >> BC;
    int A = (A_B + AB) / 2;
    int B = (B_C + BC) / 2;
    int C = (BC - B_C) / 2;
    if (A - B == A_B && B - C == B_C && A + B == AB && B + C == BC && A >= 0 &&
            B >= 0 && C >= 0) {
        cout << A << " " << B << " " << C << endl;
    } else {
        cout << "No" << endl;
    }
    return 0;
}