详细步骤:
package com.company;
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
int arr[] = {3,9,-1,10,-2};
int temp = 0;
for (int i = 0; i < arr.length - 1; i++) {
if (arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
}
System.out.println("第一遍排序后的结果");
System.out.println(Arrays.toString(arr));
for (int i = 0; i < arr.length - 2; i++) {
if (arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
}
System.out.println("第二遍排序后的结果");
System.out.println(Arrays.toString(arr));
for (int i = 0; i < arr.length - 3; i++) {
if (arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
}
System.out.println("第三遍排序后的结果");
System.out.println(Arrays.toString(arr));
for (int i = 0; i < arr.length - 4; i++) {
if (arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
}
System.out.println("第四遍排序后的结果");
System.out.println(Arrays.toString(arr));
for (int i = 0; i < arr.length - 5; i++) {
if (arr[i] > arr[i + 1]){
temp = arr[i];
arr[i] = arr[i + 1];
arr[i + 1] = temp;
}
}
System.out.println("第五遍排序后的结果");
System.out.println(Arrays.toString(arr));
}
}优化后的算法:
package com.company;
import java.util.Arrays;
public class Main {
public static void main(String[] args) {
// int arr[] = {3,9,-1,10,20};
int[] arr = {1,2,3,4,5,6,7};
int temp = 0;
boolean flag = false;// 标识变量,表示是否进行过交换
// 冒泡排序 的时间复杂度 O(n^2)
for (int i = 0; i < arr.length - 1; i++) {
for (int j = 0; j < arr.length - 1 - i; j++) {
if (arr[j] > arr[j + 1]){
flag = true;
temp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = temp;
}
}
System.out.println("第" + (i + 1) + "遍排序后的结果");
System.out.println(Arrays.toString(arr));
if (!flag){ // 在一趟排序中,一次交换都没有发生过
break;
}else {
flag = false; // 重置 flag!!!, 进行下次判断
}
}
}
}加入时间记录后:
package com.company;
import java.text.SimpleDateFormat;
import java.util.Arrays;
import java.util.Date;
public class Main {
public static void main(String[] args) {
int n = 80000;
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = (int) (Math.random() * n);
}
System.out.println(Arrays.toString(arr));
Date date = new Date();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String dateStr = simpleDateFormat.format(date);
System.out.println("排序前的时间" + dateStr);
long l1 = System.currentTimeMillis();
bubbleSort(arr);
System.out.println("排序后的数组");
Date date2 = new Date();
String date2Str = simpleDateFormat.format(date2);
System.out.println("排序后的时间" + date2Str);
long l2 = System.currentTimeMillis();
l2 = (l2 - l1) / 1000;
System.out.println("总共耗费的时间" + l2 + "" + "秒");
}
public static void bubbleSort(int[] arr) {
int temp = 0;
boolean flag = false;// 标识变量,表示是否进行过交换
// 冒泡排序 的时间复杂度 O(n^2)
for (int i = 0; i < arr.length - 1; i++) {
for (int j = 0; j < arr.length - 1 - i; j++) {
if (arr[j] > arr[j + 1]) {
flag = true;
temp = arr[j];
arr[j] = arr[j + 1];
arr[j + 1] = temp;
}
}
// System.out.println("第" + (i + 1) + "遍排序后的结果");
// System.out.println(Arrays.toString(arr));
if (!flag) { // 在一趟排序中,一次交换都没有发生过
break;
} else {
flag = false; // 重置 flag!!!, 进行下次判断
}
}
}
}
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