题解：BC55 简单计算器

```#include<stdio.h>
int main()
{
    double a,b;
    char c;
    while(scanf("%lf%c%lf",&a,&c,&b)!=EOF)
    {
        if(b!=0)
        {
        switch(c)
    {
            case '+':printf("%.4lf+%.4lf=%.4lf",a,b,a+b);break;
            case '-':printf("%.4lf-%.4lf=%.4lf",a,b,a-b);break;
            case '*':printf("%.4lf*%.4lf=%.4lf",a,b,a*b);break;
            case '/':printf("%.4lf/%.4lf=%.4lf",a,b,a/b);break;
            
    }
        }
    if(c!='+'&&c!='-'&&c!='*'&&c!='/')
        printf("Invalid operation!\n");
    if(b==0.0)
        printf("Wrong!Division by zero!\n");
        
    
    }
}

个人做法，如有错误请指正。