#include <iostream>
using namespace std;
const int N = 1e5 + 10;
//开long long 数组防止数据过大
long long sum[N], arr[N];
int main() {
int n = 0, q = 0;
cin >> n >> q;
for (int i = 1; i <= n; i++) {
cin >> arr[i];
//在定义arr数组的同时把sum数组定义,减少时间复杂度
if (i == 1) {
sum[i] = arr[i];
} else {
sum[i] = sum[i - 1] + arr[i];
}
}
while (q--) {
int l = 0, r = 0;
cin >> l >> r;
if (l == 1) {
printf("%lld\n", sum[r]);
} else {
printf("%lld\n", sum[r] - sum[l - 1]);
}
}
return 0;
}



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