切记树状数组不能处理为0的情况(lowbit无法计算,所以遇到这种情况别忘了+1)



#include<cstdio>
#include<iostream>
using namespace std;
int a[500005],b[500005];
int n;
int lowbit(int x)
{
    return x&(-x);
}
void add(int x,int y)
{
    for(int i=x;i<=n;i+=lowbit(i))
    b[i]+=y;
}
int sum(int x)
{
    int ans=0;
    for(int i=x;i;i-=lowbit(i))
    ans+=b[i];
    return ans;
}
int main()
{
    int m;
    scanf("%d%d",&n,&m);
    for(int i=1;i<=n;i++)
    {
        scanf("%d",&a[i]);
        add(i,a[i]);//切记初始化!!! 
    } 
    char pd;
    int x,y;
    for(int i=1;i<=m;i++)
    {
        cin>>pd>>x>>y;
        //scanf("%d%d%d",&pd,&x,&y);
        if(pd=='x')
        {
            add(x,y);
        }
        else
        {
            printf("%d\n",sum(y)-sum(x-1));//注意不是sum(x,y) 
        }
    }
    return 0;
}