select
    gender,university,
    count(device_id) as user_num,
    round(avg(active_days_within_30),1) as avg_active_day,
    round(avg(question_cnt),1) as avg_question_cnt
from   
    user_profile
group by
    gender ,university 
order by
    gender,university

这一题的有个要求要按照性别和学校升序进行排序,注意分组后的order排序