select gender,university, count(device_id) as user_num, round(avg(active_days_within_30),1) as avg_active_day, round(avg(question_cnt),1) as avg_question_cnt from user_profile group by gender ,university order by gender,university
这一题的有个要求要按照性别和学校升序进行排序,注意分组后的order排序