题解 | 字母统计

#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main() {
    string s;
    cin >> s;
    vector<int> a(26);
    for (int i = 0; i < s.size(); i++) {
        if (s[i] >= 'A' && s[i] <= 'Z')a[s[i] - 'A']++;
    }
    for (int i = 0; i < a.size(); i++) {
        //INT和Char计算->INT型号
        cout << char('A' + i) << ":" << a[i] << endl;
    }
}